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IND vs SA 2nd ODI: South Africa won the toss, India will bat first; See- playing eleven
Sandy Verma | December 3, 2025 4:24 PM CST

IND vs SA 2nd ODI: The second match of the three-match ODI series between India and South Africa will be played in Raipur today. The Indian team is leading 1-0 in this series and by winning the second ODI, the team will take the field with the intention of taking an unassailable lead in the series. At the same time, this will be South Africa’s last chance to save the series.

Read :- IND vs SA 2nd ODI: Team India will enter Raipur today to win the series; Know- when and where you will be able to watch the second ODI live

The toss has taken place for Raipur ODI and South Africa captain Temba Bavuma has won the toss and decided to bowl first. That means India will once again bat in the first innings. The match will be played from 01:30 pm Indian time. South Africa has made three changes in its playing eleven, while India has made no changes in its playing eleven.

Playing XI of both the teams for the second ODI

India’s playing eleven: Yashasvi Jaiswal, Rohit Sharma, Virat Kohli, Ruturaj Gaikwad, Washington Sundar, KL Rahul (wicket keeper), Ravindra Jadeja, Harshit Rana, Kuldeep Yadav, Arshdeep Singh, Prasidh Krishna.

South Africa’s playing eleven: Quinton de Kock (wk), Aiden Markram, Temba Bavuma (c), Matthew Britzke, Tony De Zorzi, Dewald Brevis, Marco Jensen, Corbin Bosch, Keshav Maharaj, Nandre Berger, Lungi Ngidi.

Read :- IND vs SA 2nd ODI: India vs South Africa 2nd ODI will be played in Raipur, Team India did not lose a single match.


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